When it comes to mathematics, every small calculation has its importance and larger calculations are built upon them. Understanding the basics of mathematics and being able to apply it to solve everyday problems is something that everyone should strive for. In this article, we will discuss the calculation of what percent of 1.20 is .80.
The Calculation Process
The calculation is rather simple, but it does involve some basic math skills. To begin, you will need to divide the number 1.20 by the number .80. This will give you an answer of 1.5. That number will be the decimal equivalent of the percent of 1.20 that .80 is.
To convert the decimal number to a percent, you will need to multiply the decimal number by 100. This will give you an answer of 150%. So the answer to the question “what percent of 1.20 is .80” is 150%.
Understanding the Concept of Percent
It is important to understand the concept of percent when performing math calculations. Percent is a way to express a fraction of a whole number in a simpler way. A percent is expressed as one hundredth (1/100) of a number. If you are asked to calculate what percent of 1.20 is .80, you are being asked to find the fraction of 1.20 that .80 is.
To calculate this, you can use the formula: (part/whole) x 100 = %. Using this formula, the calculation would look like this: (0.80/1.20) x 100 = 66.67%. This means that .80 is 66.67% of 1.20.
Conclusion
Calculating what percent of 1.20 is .80 is a simple calculation. All you need to do is divide the number 1.20 by the number .80 and then multiply the result by 100 to get the answer in percent. Using this method, the answer is 150%. Understanding the concept of percent will help you in solving many other math problems. Hopefully, this article has helped you in understanding the calculation of what percent of 1.20 is .80.
In conclusion, the answer to the question “what percent of 1.20 is .80” is 150%. This calculation involves simple math skills and understanding of the concept of percent. With the help of this article, you should be able to solve this calculation with ease.
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