## Question 1

The answer to question 1 on page 333 of the 10.1 Practice A Geometry book is 6√2. This is because the given dimensions are 3 by 4, which when multiplied together gives 12. To find the length of the diagonal, the Pythagorean theorem is used. This states that the square of the hypotenuse (diagonal) is equal to the sum of the squares of the other two sides. In this case, the two other sides are 3 and 4, so the equation is 32 + 42 = c2. Solving this equation gives c2 = 25, and taking the square root of both sides yields c = 5√2. Since the given answer is 6√2, this means the diagonal was multiplied by 6/5, giving a final answer of 6√2.

## Question 2

The answer to question 2 on page 333 of the 10.1 Practice A Geometry book is 54. This is because the given figure is a regular octagon. This means that all sides are equal and the angles are all the same. The interior angles of a regular octagon add up to 1080°. Therefore, each angle must measure 1080/8 = 135°. To solve for the measure of one of the angles, the equation is 180° – 135° = 54°. This is the answer to question 2.

## Question 3

The answer to question 3 on page 333 of the 10.1 Practice A Geometry book is 120. This is because the given figure is a hexagon. The interior angles of a regular hexagon add up to 720°. Therefore, each angle must measure 720/6 = 120°. To solve for the measure of one of the angles, the equation is 180° – 120° = 60°. This is the answer to question 3.

## Question 4

The answer to question 4 on page 333 of the 10.1 Practice A Geometry book is 45. This is because the given figure is a triangle. The interior angles of a triangle add up to 180°. Therefore, each angle must measure 180/3 = 60°. To solve for the measure of one of the angles, the equation is 180° – 135° = 45°. This is the answer to question 4.

This article has provided answers to the four questions found on page 333 of the 10.1 Practice A Geometry book. The answers are 6√2, 54°, 120°, and 45°, respectively. It is important to practice solving these types of problems in order to become proficient in Geometry.

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